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b.
A device which has a power dissipation of 150 mW in case E is to be tested at an air flow of 200 linear ft/min
and the 25C testing is to be accomplished at a case temperature of 20C. On figure 4 ĆTJ due to air flow is
+3C. The ĆTJ due to case temperature change is -5C (25-20). Therefore the total ĆTJ = -5C +3C = -2C.
Using figure 6, find the +25C, -ĆTJ column. To adjust VOL(max) locate the limit coefficient corresponding to
VOL(max) for a negative ĆTJ, this value is 0.44 mVC. Multiply the ĆTJ by the coefficient and algebraically add
it to the +25C VOL(max) limit from table III.
VOL(max) (adjusted limits) = (-2C) x (0.44 mV/C) + (-1620 mV)
= -.88 mV -1620 mV = -1620.88 mV
Use -1621 mV
Follow the same procedure to adjust the remaining parameters at +25C.
6.9 Changes from previous issue. Marginal notations are not used in this revision to identify changes with respect
to the previous issue due to the extensiveness of the changes.
Custodians:
Preparing activity:
Army - CR
DLA - CC
Navy - EC
Air Force - 11
(Project 5962-2005-044)
DLA - CC
Review activities:
Army - MI, SM
Navy - AS, CG, MC, SH, TD
Air Force - 03, 19, 99
NOTE: The activities listed above were interested in this document as of the date of this document. Since
organizations and responsibilities can change, you should verify the currency of the information above using the
ASSIST Online database at http://assist.daps.dla.mil.
22
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